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Automatically pin the Cornerpin in Nuke

satheesrev
Mar 16, 2024
1 min read

This little code place the cornerPin nodes 4 pin's automatically based on the bbox. If your image dosen't have bbox add a crop node and crop it as per your need.


import nuke


def autoPinning():

    selNode = None

    try:

      selNode = nuke.selectedNode()

    except ValueError:  # no node selected

      pass


    if selNode is not None:

    ## auto pin for from

        selNode['from1'].setExpression('[value name].bbox.x', 0)

        selNode['from1'].setExpression('[value name].bbox.y', 1)

        selNode['from1'].clearAnimated()

        selNode['from2'].setExpression('[value name].bbox.r', 0)

        selNode['from2'].setExpression('[value name].bbox.y', 1)

        selNode['from2'].clearAnimated()

        selNode['from3'].setExpression('[value name].bbox.r', 0)

        selNode['from3'].setExpression('[value name].bbox.t', 1)

        selNode['from3'].clearAnimated()

        selNode['from4'].setExpression('[value name].bbox.x', 0)

        selNode['from4'].setExpression('[value name].bbox.t', 1)

        selNode['from4'].clearAnimated()


    ## copying value's from

        selNode['to1'].setExpression('[value name].bbox.x', 0)

        selNode['to1'].setExpression('[value name].bbox.y', 1)

        selNode['to1'].clearAnimated()

        selNode['to2'].setExpression('[value name].bbox.r', 0)

        selNode['to2'].setExpression('[value name].bbox.y', 1)

        selNode['to2'].clearAnimated()

        selNode['to3'].setExpression('[value name].bbox.r', 0)

        selNode['to3'].setExpression('[value name].bbox.t', 1)

        selNode['to3'].clearAnimated()

        selNode['to4'].setExpression('[value name].bbox.x', 0)

        selNode['to4'].setExpression('[value name].bbox.t', 1)

        selNode['to4'].clearAnimated()



    else:

      nuke.message('No node selected')

 
 
 

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